A 87.9 kg clock initially at rest on a horizontal floor requires a 659.2 N horizontal force to set it in motion.
After the clock is in motion, a horizontal force of 556.0 N keeps it moving with a constant speed.
Find the coefficient of kinetic (sliding) friction of the clock on the ground, µk
+33658 See the answer here, http://web2.0calc.com/questions/stuck-help-me#r104866 but replace the 659.2 by 556.0.
+33658 See the answer here, http://web2.0calc.com/questions/stuck-help-me#r104866 but replace the 659.2 by 556.0.
