A projectile of mass 1.07 kg is shot straight up with an initial speed of 29.3 m/s. If the projectile rises to a maximum height of only 40 m, determine the magnitude of the average force due to air resistance.
+33654 If we assume the average resistance acts as a constant force, F, which adds to the gravitational force, then we have a constant acceleration (or deceleration in this case) of a = -(9.81+F/1.07). Using the constant acceleration formula v2 = u2 + 2*a*s, where v is final velocity (0), u is initial velocity (29.3) and s is distance travelled (40) we have
0 = 29.32 - 2*(9.81+F/1.07)*40
It's a straightforward matter to find F from this.
+33654 If we assume the average resistance acts as a constant force, F, which adds to the gravitational force, then we have a constant acceleration (or deceleration in this case) of a = -(9.81+F/1.07). Using the constant acceleration formula v2 = u2 + 2*a*s, where v is final velocity (0), u is initial velocity (29.3) and s is distance travelled (40) we have
0 = 29.32 - 2*(9.81+F/1.07)*40
It's a straightforward matter to find F from this.
