a survey asked 120 working teenagers how satsified they are with their current employment. 90 teens said they are mostly satsified with thei

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a survey asked 120 working teenagers how satsified they are with their current employment. 90 teens said they are mostly satsified with thei

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a survey asked 120 working teenagers how satsified they are with their current employment. 90 teens said they are mostly satsified with their current empoyment. The margin of error for the survey is +-3%. find the interval in which the actual percent is likely to lie.

Guest Oct 16, 2014

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The percentage of 90 out of 120 is 90 / 120 = .75 = 75%.

Since the error is ±3%, one would expect the true percentage to be between 75% - 3% = 72% at the low end and 75% + 3% = 78% at the high end.

geno3141 Oct 16, 2014

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geno3141 · Answer 1 · 2014-10-16T08:36:33

The percentage of 90 out of 120 is 90 / 120 = .75 = 75%.

Since the error is ±3%, one would expect the true percentage to be between 75% - 3% = 72% at the low end and 75% + 3% = 78% at the high end.

a survey asked 120 working teenagers how satsified they are with their current employment. 90 teens said they are mostly satsified with thei

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