+136 A surveyor determines that the angle of elevation to the top of a vertical building from a pt on level ground is 38deg. She then moves back 50 feet & determines that the angle of elevation is 32 deg. Find the height of the building.
It'd be greatly appreciated if steps would be shown of how to solve it!
+26367 A surveyor determines that the angle of elevation to the top of a vertical building from a pt on level ground is 38deg.
She then moves back 50 feet & determines that the angle of elevation is 32 deg.
Find the height of the building.
\(\begin{array}{|rcll|} \hline \dfrac{\sin(6^\circ)}{50} &=& \dfrac{\sin(32^\circ)}{y} \\ \mathbf{y} &=& \mathbf{ \dfrac{50\sin(32^\circ)}{\sin(6^\circ)} } \\ \hline \end{array}\)
\(\begin{array}{|rcll|} \hline \sin(38^\circ) &=& \dfrac{h}{y} \\ h &=& y\sin(38^\circ) \\ h &=& \dfrac{50\sin(32^\circ)\sin(38^\circ)}{\sin(6^\circ)} \\ \mathbf{h} &=& \mathbf{ 156\ \text{feet} } \\ \hline \end{array} \)
