1.
Which description is correct for the x-intercept(s) of Function A and Function B?
Function A:
x | g(x) |
---|---|
0 | −3 |
7 | 2 |
−2 | 0 |
1 | 0 |
4 | −5 |
Function B: f(x)=|x|−4
Function A has two x-intercepts.
Function B has one x-intercept.
Both functions have the same x-intercept(s).
Each function has one x-intercept.
Each function has two x-intercepts.
2.
Which comparison is correct for the values of f(x) and g(x) when x=−3?
Function A: f(x)=−x2+4
Function B:
xg(x)
−5−2
−40
−31
−24
Thanks so much for all your help!
x-intercepts occur where y= 0
Function A has TWO at x=-2 and x=1
Function B has TWO where x = 4 and -4
A when x = -3 - (-3)^2 +4 = -5
B when x = -3 =1 (given) Whatever choice matches this...you didnt list one that does.
1.
Function A:
x | g(x) |
0 | -3 |
7 | 2 |
-2 | 0 |
1 | 0 |
4 | -5 |
Function B:
f(x) = |x| − 4
The x-intercepts of a function are the x values when that make the function equal 0.
In function A, the x-intercepts are -2 and 1 .
In Function B, the x-intercepts are 4 and -4 .
So each function has two x-intercepts.
2.
Function A:
f(x) = -x2 + 4
Function B:
x | g(x) |
-5 | -2 |
-4 | 0 |
-3 | 1 |
-2 | 4 |
When x = -3 , f(x) = f(-3) = -(-3)2 + 4 = -9 + 4 = -5
When x = -3 , g(x) = g(-3) = 1
-5 < 1 so...
f(-3) < g(-3)