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Algebra

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Solve the inequality 4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1). Write your answer in interval notation.

bingboy Jan 18, 2025

Best Answer

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$4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1)$

When you combine like terms and simplify, you get

$4t^2 \le -13t+35+4t^2-1$ which turns into

$13t \le 34$

Divide both sides by 13:

$t \le 34/13$

So the answer in interval notation is $(-\infty,34/13)$

Owinner Jan 19, 2025

1⁺⁰ Answers

+28

+1

Best Answer

$4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1)$

When you combine like terms and simplify, you get

$4t^2 \le -13t+35+4t^2-1$ which turns into

$13t \le 34$

Divide both sides by 13:

$t \le 34/13$

So the answer in interval notation is $(-\infty,34/13)$

Owinner Jan 19, 2025

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