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The parabola y = ax^2 + bx + c is graphed below. Find a + b + c. (The grid lines are one unit apart.)
The parabola passes through (-2,8), (0,0), and (2,8).

 Jan 20, 2025

Best Answer 

 #1
avatar+28 
+1
We can plug in the points into the standard form of a parabola to get a, b, and c.

 

First, notice that c must be equal to 0 because when you plug in (0,0) in, you get c=0. That way, we only have to solve for 2 variables.

 

Now we can plug in the rest of the points, and we get the equations 8=4a2b and 8=4a+2b.

 

We can set the equations equal to each other and then we get b=0 as well.

 

Plugging b=0 into the equations, we get a=2. So a+b+c is 2+0+0 which is 2

 

  

 Jan 20, 2025
 #1
avatar+28 
+1
Best AnswerWe can plug in the points into the standard form of a parabola to get a, b, and c.

 

First, notice that c must be equal to 0 because when you plug in (0,0) in, you get c=0. That way, we only have to solve for 2 variables.

 

Now we can plug in the rest of the points, and we get the equations 8=4a2b and 8=4a+2b.

 

We can set the equations equal to each other and then we get b=0 as well.

 

Plugging b=0 into the equations, we get a=2. So a+b+c is 2+0+0 which is 2

 

  

Owinner Jan 20, 2025

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