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One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Jul 21, 2024
 #1
avatar+1946 
+1

We can use subsitution to our advantage. 

Now, first, let's put a terms of b. From the second equation, we get that

a=4b2

 

Subsituting this value of x into the first equation, we get

4b2b4=48

 

Now, the top and the bottom cancel out, so we have

4b2=48b2=12b=23,b=23

 

Thus, we find two values of b. We have

b=23,b=23

 

Thanks! :)

 Jul 21, 2024
edited by NotThatSmart  Jul 21, 2024
 #2
avatar+35 
+2

 

We could do ab4/ab2=48/4

So the A will cancel out and we will be left with b2=12

So the answer is 23 or23

 Jul 22, 2024

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