antiderivitive of cosh(x/361)

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Guest Oct 12, 2014

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The integral of cosh(ax) dx is (1/a)sinh(ax) + C

IN this case a = 1/361; (1/a)sinh(ax) + C = (361)sinh( (1/361)x ) + C

geno3141 Oct 12, 2014

geno3141 · Answer 1 · 2014-10-12T01:44:03

The integral of cosh(ax) dx is (1/a)sinh(ax) + C

IN this case a = 1/361; (1/a)sinh(ax) + C = (361)sinh( (1/361)x ) + C