5 √ 32x5z10 (is not a check mark, but a square root)
possibles are
2z5
2xz5
2z2
2xz2
[ (32·x^5·z^10) ]^(1/5) = [ (2^5·x^5·z^10) ]^(1/5)
Since it's a power to a power, multiply the exponents together:
[ 2 ^ ( 5 · 1/5) ] · [ x ^ ( 5 · 1/5) ] · [ z ^ (10 · 1/5) ]
= 2^1 · x^1 · z^2
= 2xz²