Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
+1
4069
1
avatar

Below is the graph of f(x) = \dfrac{a^x}{b}, where a and b are integers. Find a+b

(Each little square measures 1 unit by 1 unit.) 

size(250);real ticklen=3;real tickspace=2;real ticklength=0.1cm;real axisarrowsize=0.14cm;pen axispen=black+1.3bp;real vector...

 Dec 11, 2014

Best Answer 

 #1
avatar+23254 
+6

Two of the points on the graph are (2, -2)  and (3, -8)

f(x)  =  ax/b

(2, -2)   --->   a2/b  =  -2     --->   a2  =  -2b     --->    a2/-2  =  b

(3, -8)   --->   a3/b  =  -8     --->   a3  =  -8b     --->    a3/-8  =  b

Setting the first equation equal to the second:     a2/-2   =   a3/-8 

Multiplying both sides by -8:                               4a2   =   a3

Dividing both sides by  a2  (This step is allowed provided that a2  ≠ 0):       4  =  a

Since  a2/b  =  -2  and  a  =  4:  16/b  =  -2     --->   b  =  -8

Now, find a + b:

 Dec 11, 2014
 #1
avatar+23254 
+6
Best Answer

Two of the points on the graph are (2, -2)  and (3, -8)

f(x)  =  ax/b

(2, -2)   --->   a2/b  =  -2     --->   a2  =  -2b     --->    a2/-2  =  b

(3, -8)   --->   a3/b  =  -8     --->   a3  =  -8b     --->    a3/-8  =  b

Setting the first equation equal to the second:     a2/-2   =   a3/-8 

Multiplying both sides by -8:                               4a2   =   a3

Dividing both sides by  a2  (This step is allowed provided that a2  ≠ 0):       4  =  a

Since  a2/b  =  -2  and  a  =  4:  16/b  =  -2     --->   b  =  -8

Now, find a + b:

geno3141 Dec 11, 2014

2 Online Users

avatar