+0  
 
0
705
3
avatar+2498 

                                          

 Jan 19, 2016

Best Answer 

 #2
avatar+128613 
+20

We can solve this equation, Solveit

 

30(3/5)N  =  4      where N is the number of bounces.....  divide both sides by 30

 

(3/5)N  = 4/30

 

(.6)N  = 2/15    take the log of each side

 

log (.6)N  = log (2/15)     and we can write

 

N log(.6) = log(2/15)     divide both sides by log(.6)

 

N = log(2/15) / log(.6)

 

N  ≈ 3.944    

 

When N = 3.....the ball height = 6.48 ft

 

When N = 4.......the ball height = 3.88 ft

 

So......it looks like that on the 4th bounce, the ball will be at a height of less than 4 ft   (B)

 

 

 

cool cool cool

 Jan 19, 2016
edited by CPhill  Jan 19, 2016
 #1
avatar
+10

My guess is( B), because (3/5)^4 X 30 feet=3.888 feet after the 4th bounce.

 Jan 19, 2016
 #2
avatar+128613 
+20
Best Answer

We can solve this equation, Solveit

 

30(3/5)N  =  4      where N is the number of bounces.....  divide both sides by 30

 

(3/5)N  = 4/30

 

(.6)N  = 2/15    take the log of each side

 

log (.6)N  = log (2/15)     and we can write

 

N log(.6) = log(2/15)     divide both sides by log(.6)

 

N = log(2/15) / log(.6)

 

N  ≈ 3.944    

 

When N = 3.....the ball height = 6.48 ft

 

When N = 4.......the ball height = 3.88 ft

 

So......it looks like that on the 4th bounce, the ball will be at a height of less than 4 ft   (B)

 

 

 

cool cool cool

CPhill Jan 19, 2016
edited by CPhill  Jan 19, 2016
 #3
avatar+2498 
+10

I just didn t  understand the question but now i understood thanks CPhill and Guest ! :)

 Jan 19, 2016

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