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Q .If θ1,θ2 and θ3 are three values lying in [0, 3(π)] for which tanθ=λ .Then [(tan θ1/2)*(tan θ2/2)+ (tan θ2/2*(tan θ3/2)+(tan θ3/2)*(tan θ1/2)] is equal to

 
 Jul 24, 2018

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