e^(i*pi)+1

Question

0

936

1

+4

How does e^(i*3.14159265359)+1

e^(i*pi)+1

e^(3.14159265359i)+1

prove God exists

Aashu Apr 22, 2014

+33654

+5

Best Answer

It doesn't!

But it does equal zero:

${{\mathtt{e}}}^{\left({i}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}}$

This is a famous equation known as Euler's equation.

Alan Apr 22, 2014

Alan · Answer 1 · 2014-04-22T05:57:17

It doesn't!

But it does equal zero:

${{\mathtt{e}}}^{\left({i}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}}$

This is a famous equation known as Euler's equation.