Expand this binomial power (x^2+2/x)^4

If you can't use the calculator:

If you use Pascal's triangle to get the coefficients:

Row 0:                                1

Row 1:                             1     1

Row 2:                         1      2       1

Row 3:                     1      3      3       1

Row 4:                  1     4       6      4      1                      

(a + b) ^ 4  =  1a^4  +  4a^3b  +  6a^2b^2  +  4ab^3  + 1b^4

In (x² + 2/x)^4,  a = x²   and   b = 2/x

                       1(x²)^4  +  4(x²)^3(2/x)  +  6(x²)^2(2/x)^2  +  4(x²)(2/x)^3  +  1(2/x)^4

                            x^8  +  4(x^6)(2/x)  +  6(x^4)(4/x²)  +  4(x²)(8/x^3)  + 16/x^4

                            x^8  +  8/x^5  +  24x^2  +  32/x  +  16/x^4

A procedure that isn't as easy as doing it by calculator, and a way in which more mistakes can be made!

If you must do it by hand and if you know combinations (nCr) you don't need to use Pascal's triangle to find the coefficients: the coefficients of row 4 are:   4C0,  4C1,   4C2,   4C3,   4C4

Expand this binomial power (x^2+2/x)^4