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Find the exact values of the six trig function of 270 degrees

 Dec 16, 2014

Best Answer 

 #1
avatar+23254 
+5

On the unit circle, the coordinates of a 270° angle are (0, -1).  

At this point x-value = 0, y-value = -1, r-value (the distance from the origin to the point) = 1.

sin = y/r          cos = x/r        tan = y/x        csc = r/y        sec = r/x        cot  =  x/y

sin(270°)  =  -1/1  =  -1                            csc(270°)  =  1/-1  =  -1

cos(270°)  =  0/1  =  0                              sec(270°)  =  1/0  =  undefined

tan(270°)  =  -1/0  =  undefined               cot(270°)  =  0/-1  =  0

 Dec 17, 2014
 #1
avatar+23254 
+5
Best Answer

On the unit circle, the coordinates of a 270° angle are (0, -1).  

At this point x-value = 0, y-value = -1, r-value (the distance from the origin to the point) = 1.

sin = y/r          cos = x/r        tan = y/x        csc = r/y        sec = r/x        cot  =  x/y

sin(270°)  =  -1/1  =  -1                            csc(270°)  =  1/-1  =  -1

cos(270°)  =  0/1  =  0                              sec(270°)  =  1/0  =  undefined

tan(270°)  =  -1/0  =  undefined               cot(270°)  =  0/-1  =  0

geno3141 Dec 17, 2014

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