Find the third iterate of the function f(t) = 9t - 3 when t0 = 1/3 + i/9.
A)81i - 30
B)9i - 3
C)729i - 273
D)9i -270
t0 = 1/3 + i/9
f(t) = 9t - 3
---> f(1) = 9[1/3 + i/9] - 3 = 3 + i - 3 = i
---> t(2) = 9[i] - 3 = 9i - 3
---> t(3) = 9[9i - 3] - 3 = 81t - 27 - 3 = 81i - 30
