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2/3^-(2/3) how would you solve something like this

 Oct 10, 2014

Best Answer 

 #1
avatar+23254 
+5

I am going to assume that the problem is:  2 / [3^-(2/3)]

First, a negative exponent means that that factor is in the wrong place in the fraction; since it is in the denominator, place it into the numerator and change the exponent to a positive:

2 · 3^(2/3)

In the exponent, the 2 means square the number; the 3 means find the cube root of the number. 3² will give you 9; but it doesn't have a nice cube root.

So, this is not going to be simplified any further without using a calculator.

 Oct 10, 2014
 #1
avatar+23254 
+5
Best Answer

I am going to assume that the problem is:  2 / [3^-(2/3)]

First, a negative exponent means that that factor is in the wrong place in the fraction; since it is in the denominator, place it into the numerator and change the exponent to a positive:

2 · 3^(2/3)

In the exponent, the 2 means square the number; the 3 means find the cube root of the number. 3² will give you 9; but it doesn't have a nice cube root.

So, this is not going to be simplified any further without using a calculator.

geno3141 Oct 10, 2014

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