Functions

\(g(2x)=\sqrt[3]{\frac{2x+3}{4}}\)

\(2g(x)=2*\sqrt[3]{\frac{x+3}{4}}\)

Cubing both sides, we get \(\frac{2x+3}{4}=2x+6\)

Multiplying by 4, we get \(2x+3=8x+24\)

So \(x=-3.5\)\(\)

g (2x)  =  ³√ [  (2x + 3) / 4 ]    (1)  

2 (g(x) ) =  2 * ³ √  [ (x + 3 ) / 4 ]    (2)

Let  us  cube  (1) , (2)  and set them equal...so we have...

(2x + 3) / 4  =  8 (x + 3) / 4

(2x + 3)  = 8(x + 3)

2x +  3  = 8x + 24

-21  = 6x

x  = -21/6  =  -7/2

Thank you! Great!