g(x)=6-x h(x)=x3 find for : h(-3) , hg(2) , gh(2)

g(x)  =  6 - x         h(x)  =  x³

h(-3)   --->   place -3 in for x into the h(x) formula:  h(-3)  =  (-3)³  =  -27

hg(2)   --->   h( g(2) )

     first, calculate g(2):  g(2)  =  6 - 2  =  4

     then, place this result into the h formula:

     --->   h( g(2) )  =  h(4)  =  4³  =  64

gh(2)   --->   g( h(2) )

     first, calculate h(2):  h(2)  =  2³  =  8

     then, place this result into the g formula:

     --->   g( h(2) )  =  g( 8 )  =  6 - 8  =  2

You need to work the functions from right to left:  hg(x)  =  h( g(x) )     and     gh(x)  =  g( h(x) )