Help 29,30
29.
We want to permute all possible orders of selecting any 3 students from 10....so we have
P (10,3) = 720 ways
30.
We have 36 possible outcomes.....the ones that sum to 6 are
1,5
5,1
4,2
2,4
3,3 = 5 ways
So...the probabilitiy is 5 / 36