Cody buys a soda that offers another soda free if he is lucky. The cap reads '1 in 6 wins!', meaning that each soda has a 1/6 probability of winning. Cody sees this and buys six of these sodas, thinking he is guaranteed a seventh. What is the true probability he will win at least one more soda? Express your answer as decimal to the nearest hundredth.
I THINK:
he has a 5/6 chance of NOT winning a soda each time
(5/6)6 = .335 chance of NOT winning a soda with six purchases
1- .335 = .665 chance of WINNING with a six-pak purchase 66.5%