+152 Let line l1 be the graph of 5x+8y=−9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx+b, then find m+b.
+37165 l1 is re-written as y = -5/8 x -9/8 slope m is -5/8
l2 perpindicular slope is -1/(-5/8) = 8/5
y = 8/5 x + b sub in point 10,10
10 = 8/5 (10) + b
b = 10 - 80/5 = -30/5
-30/5 +8/5= -22/5
