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If \(7^{x+1} = 4\), what is \(7^{2x - 1}\)?

Guest Jul 7, 2020

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Square both sides

(7^x+1)²= 4²now multiply both sides by 7^-3

(7^x+1)² (7^-3 ) = 4²(7^-3)

7^2x-1= 16/343 = ...........

ElectricPavlov Jul 7, 2020

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