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672

3

+2498

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Solveit Jan 16, 2016

+128631

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Best Answer

Look at the graph here, Solveit : https://www.desmos.com/calculator/ogakicvciq

Note that, for every point (a,b) on the graph y = 2/x² , the point (b, a) exists on the graph y = 2/y²

Thus, both graphs, with respect to each other, are symmetric about the line y = x

CPhill Jan 16, 2016

CPhill · Answer 1 · 2016-01-16T07:16:05

Look at the graph here, Solveit : https://www.desmos.com/calculator/ogakicvciq

Note that, for every point (a,b) on the graph y = 2/x² , the point (b, a) exists on the graph y = 2/y²

Thus, both graphs, with respect to each other, are symmetric about the line y = x

Guest · Answer 2 · 2016-01-16T04:48:51

Graph the first equation using the calculator.

Solve the second equation for y

y = sqrt(2/x) and graph it..... I think the answer is 'E'

Solveit · Answer 3 · 2016-01-16T07:28:59

thanks CPhill and Guest !