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how can i make a triangle with the hypotenuse of square root of 80

 Nov 16, 2016
edited by Guest  Nov 16, 2016
 #1
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You need a line of length √5, and at one end of it draw a perpendicular line of length 4. Join their ends to form the hypotenuse and applying the wisdom of Pythagoras this third line will be of length √80. 😁 😁 😁

 

But wait! Where do you find that first line of length √5? You must construct it also—as the hypotenuse of a ∆ having base=1 and whose height=2.

 

🃏 🎡 📉 📈 

 Nov 16, 2016
 #2
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 If you think my first answer sounds more complicated than you'd prefer, then just draw a right-angled triangle with base=4 and height=8 and Pythagoras says the hypotenuse will be √80. 😛

 

🐵  🐧  🐸 

 Nov 16, 2016

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