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If ${2}^{{2020}}-{2}^{{2019}}-{2}^{{2018}}+{2}^{{2017}} = \ {k}\times {2}^{{2017}}$ , find k.

Guest Jul 8, 2020

tertre · Answer 1 · 2020-07-08T03:14:49

Notice that if we factor out $2^{2017}$ from each term on the left side, we have:

$2^{2017}(2^3-2^2-2^1+1)=2^{2017}(3)$

Thus, the value of $k$ is three(3).