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Hey! Can anyone help me?

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The easiest way to solve this triangle (find the measures of the angles A, B, and C) is

(1) Find cos-1 .28 = B.

(2) Then find A = (180º-B).

(1) Find cos-1 .96 = B.

(2) Then find A = (90º-B).

(1) Find cos-1 .96 = A.

(2) Then find B = (180º-A).

(1) Find sin-1 .28 = A.

(2) Then find B = (90º-A).

Guest Oct 10, 2014

Best Answer

+23254

+5

cos = adj/hyp sin = opp/hyp

1) For angle B, adj = 7 and hyp = 25; so cos B = 7/25 = .28

This works; but A = 90 - B.

2) Isn't correct; cos B = .28 not .96

3) For angle A, opp = 7 and hyp = 25; so sin A = 7/25 = .28 and B is found by 90 - A.

geno3141 Oct 10, 2014

1⁺⁰ Answers

+23254

+5

Best Answer

cos = adj/hyp sin = opp/hyp

1) For angle B, adj = 7 and hyp = 25; so cos B = 7/25 = .28

This works; but A = 90 - B.

2) Isn't correct; cos B = .28 not .96

3) For angle A, opp = 7 and hyp = 25; so sin A = 7/25 = .28 and B is found by 90 - A.

geno3141 Oct 10, 2014

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