\displaystyle \int_1^2 \frac{(x+3)^2}{3} dx\\
Using the substitution u=x+3, du=dx, we have the change of integration boundary {x=1⟹u=4x=2⟹u=5. Then we have ∫21(x+3)23dx=13∫54u2du. You can use the power rule to integrate it. Note that ∫baf(x)dx=F(b)−F(a) where F is an antiderivative of f.
i need teaching of this pls help
You can pretty much learn on your own using some online resources.
They are called integrals, and anti- derivatives. you can search them up :)
Kakashi, you are being a pest.
This mathematics is way over your head and you know that.
Thanks for your answer Max.