How can I solve for sec 100° 0' 5" ?

sec(100+5/360)

$${sec}{\left({\mathtt{100}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{360}}}}\right)} = -{\mathtt{5.750\: \!864\: \!607\: \!877\: \!902\: \!7}}$$

sec(100° 0' 5")  =  1 / cos(100° 0' 5")