how to get the focus of parbola

If you have the equation of a parabola in vertex form y = a(x - h)² + k, then the vertex is at (h, k) and the focus is (h, k + 1/(4a)). Notice that here we are working with a parabola with a vertical axis of symmetry, so the x-coordinate of the focus is the same as the x-coordinate of the vertex

If the equation is in the form:  y  =  a(x - h)² + k

then the vertex is the point (h, k) and the focal point is the point (h, k + 1/(4a)).

If you need further information, please repost with specific questions.

if it is in the form      $$(x-h)^2=4a(y-k)$$

then the vertex is (h,k)

The focal length is     $$|a|$$               (note that a can be negative)

So the focus will be      $$(h, k+a)$$