how would one solve the following equation for n? : (2.12x10^-18)= (-2.18x10^-18)[(1/(n^2))-(1/36)]

2.12 x 10^-18  =  (-2.18 x 10^-18) x [ 1/n² - 1/36 ]

Divide both sides by (-2.18 x 10^-18):

Since  [2.12 x 10^-18] ÷ [-2.18 x 10^-18]  =  -0.972       (The 10^-18's cancel.)

   -0.972  =  1/n² - 1/36

Add 1/36 to both sides:

   -0.945  =  1/n²

This has no real solutions, because you can't square a number and get a negative result.

Thank you! I did the same thing, but thought I was doing something wrong because I kept getting a negative number. Thanks!