I can't figure out the standard form of a line with the coordinates (4,6) and (1,5). I've worked it out many times and I can't get the right

The point-slope form is:  y - y1  =  m(x - x1)

If you call the point (4,6) =(x1,y1)

and if you find the slope:  m  =  (y2 - y1) / (x2 - x1)

                                     m  =  (5 - 6) / (1 - 4)  =  -1 / -3  =  1/3

Substitting these into the point-slope form:  y - 6 = (1/3)(x - 4)

             multiplying both sides by 3:         3y - 18  =  1(x - 4)

             simplifying:                                 3y - 18  =  x - 4

                                                               -x + 3y  =  14

                                                                 x - 3y  =  -14

You are so helpful! Thank you.