+26367 In the formula \(P = \frac{7}{12}\cdot Q +60\), if P is increased by 35, then what is the increase in Q?
\(\begin{array}{rcl} P+35 &=& \frac{7}{12}\cdot (Q+x) +60 \\ P+35 &=& \frac{7}{12}\cdot Q + \frac{7}{12}\cdot x +60 \\ P+35 &=& \underbrace{\frac{7}{12}\cdot Q + 60}_{=P} +\frac{7}{12}\cdot x\\ P+35 &=& P +\frac{7}{12}\cdot x\\ 35 &=& \frac{7}{12}\cdot x\\ \frac{7}{12}\cdot x &=& 35\\ x &=& 35\cdot \frac{12}{7} \\ \mathbf{x} & \mathbf{=} & \mathbf{60} \\ \end{array}\)
the answer is (B)
Q should increase in inverse proportion to 7/12, or:
12/7 X 35=60, so the answer would be "B"
+8581 Ugh! apparently i was talking bad about someone, now there saying that there going to fight me.
+8581 I said that they need to quit bossing me around, telling me what to do, trying to make me their servant.
+2498 if you are right and if they are your frends they need to understood you and what about you never talk behind your frends or classmates if you need smth say to them . (noone gonna to fight you because of that )
+26367 In the formula \(P = \frac{7}{12}\cdot Q +60\), if P is increased by 35, then what is the increase in Q?
\(\begin{array}{rcl} P+35 &=& \frac{7}{12}\cdot (Q+x) +60 \\ P+35 &=& \frac{7}{12}\cdot Q + \frac{7}{12}\cdot x +60 \\ P+35 &=& \underbrace{\frac{7}{12}\cdot Q + 60}_{=P} +\frac{7}{12}\cdot x\\ P+35 &=& P +\frac{7}{12}\cdot x\\ 35 &=& \frac{7}{12}\cdot x\\ \frac{7}{12}\cdot x &=& 35\\ x &=& 35\cdot \frac{12}{7} \\ \mathbf{x} & \mathbf{=} & \mathbf{60} \\ \end{array}\)
the answer is (B)
+128631 Note.....7/12 is the slope of the line relating P and Q.........this means that, everytime P changes by 7, Q changes by 12
So....using a proportion.....change in P / change in Q =
7/12 = 35/ change in Q cross-multiply
7 * change in Q = 35 * 12 divide by 7
change in Q = 35* 12 / 7
change in Q = [35/7] * 12
change in Q = 5 * 12
change in Q = 60 → (B)
