i have a equation for calculating water capacity, H=capacity. log(0.33H)=0.83log69. its been a long time and I have forgotten the sequence t

0.83log69  =  log(69^.83)    (multipliers go into logs as exponents)

log(0.33H)  = log(69^.83)

If the log is base b:                          (It doesn't make any diference if the base is 10 or e.}

b^log(0.33H)  =  b^log(69^.83)

0.33H  =  69^.83

H  =  (69^.83) / 0.33