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i need help on my sci. home work a boulder on top of a cliff has the potential energy of 8,800 J and has twice the mass of the boulder next to it. what is the GPE of the smaller boulder? can you exsplane to me to to slove this?

physics
 Nov 6, 2014

Best Answer 

 #1
avatar+23254 
+10

the formula for potential energy is:  P.E.  =  m·g·h

The values for g (acceleration due to gravity) and h (height) will be the same for both boulders.

The only difference will be in their masses.

If the the boulder with the P.E. of 8,800 J has twice the mass as the other boulder, then it must have twice the P.E. of the other boulder.  The P.E. of the smaller boulder is 4,400 J.

 Nov 6, 2014
 #1
avatar+23254 
+10
Best Answer

the formula for potential energy is:  P.E.  =  m·g·h

The values for g (acceleration due to gravity) and h (height) will be the same for both boulders.

The only difference will be in their masses.

If the the boulder with the P.E. of 8,800 J has twice the mass as the other boulder, then it must have twice the P.E. of the other boulder.  The P.E. of the smaller boulder is 4,400 J.

geno3141 Nov 6, 2014

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