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If cosA is 3/5, what is sinA and tanA?

 Dec 10, 2014

Best Answer 

 #1
avatar+23254 
+5

Picture a right triangle with the right angle being ∠C. Label the other two angles ∠A and ∠B.

cos is defined to be the ratio of the adjacent side to the hypotenuse.

In this triangle, AB is the hypotenuse, side AC is the side adjacent to ∠A and side BC is the side opposite to ∠A.

cos∠A  =  3/5  =  AC/AB

Since this is a right triangle, use the Pythagorean Theorem to find the value of the third side:

   AC² + BC²  =  AB²     --->     3² + BC²  =  5²      --->   BC  =  4

sin is defined to be the ratio of the opposite side to the hypotenuse.

sin∠A  =  BC/AB  =  4/5

tan is defined to be the ratio of the opposite side to the adjacent side.

tan∠A  =  BC/AC  =  4/3

 Dec 10, 2014
 #1
avatar+23254 
+5
Best Answer

Picture a right triangle with the right angle being ∠C. Label the other two angles ∠A and ∠B.

cos is defined to be the ratio of the adjacent side to the hypotenuse.

In this triangle, AB is the hypotenuse, side AC is the side adjacent to ∠A and side BC is the side opposite to ∠A.

cos∠A  =  3/5  =  AC/AB

Since this is a right triangle, use the Pythagorean Theorem to find the value of the third side:

   AC² + BC²  =  AB²     --->     3² + BC²  =  5²      --->   BC  =  4

sin is defined to be the ratio of the opposite side to the hypotenuse.

sin∠A  =  BC/AB  =  4/5

tan is defined to be the ratio of the opposite side to the adjacent side.

tan∠A  =  BC/AC  =  4/3

geno3141 Dec 10, 2014

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