+0  
 
0
1097
6
avatar+1995 

If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the second voltmeter (V2) read?

   

   

0.35 V

0.96 V

2.4 V

4.8 V

 

4.8 i think ?

 Apr 22, 2020
 #1
avatar+36916 
+1

We already determined the current through the circuit (in a previous question)

    I R4 = Voltage         R4 = 5 ohms    and current was from previous Q

 Apr 22, 2020
 #2
avatar+1995 
0

ops im sorry i submitted the wrong one!

jjennylove  Apr 22, 2020
 #3
avatar+1995 
0

For this circuit, what will be the voltage drop across R3 ?


   

21.3 V

14.2 V

45.0 V

9.47 V

 

i meant this one

jjennylove  Apr 22, 2020
 #4
avatar+1995 
0

it would be 45.0 right?

jjennylove  Apr 22, 2020
 #5
avatar+36916 
+2

NO.......frown

Current in the circuit      v/r = i

 

45/(20+30+45) = 473 mA

 

Votage across  R3   =  IR =  .473 * 45 = 21.3 v

 

 

ALL of the voltage will be dropped around the circuit .....45 v will be dropped

   R3  portion will be a fraction     45 / (20+30+45)    x 45 v = 21.3 v

 Apr 22, 2020
 #6
avatar+1995 
0

im so sorry, i dont know why i cant seem to understand these! it makes sense what you have wrote, i jsut hope i can apply to the others! thank you

jjennylove  Apr 22, 2020

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