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If s is a real number, then what is the smallest possible value of 2s^2 - 8s + 19?

 Oct 29, 2014

Best Answer 

 #1
avatar+23254 
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This is the equation of a parabola. Since this parabola opens upward, the vertex will be the lowest point. The x-value of the vertex is found by  -b/(2a).

a = 2    b = -8     --->     -(-8)/(2·2)  =  8/4  =  2

f(4) = 2(2)² - 8(2) + 19  =  11     <---  The minimum value of the function.

 Oct 30, 2014
 #1
avatar+23254 
+5
Best Answer

This is the equation of a parabola. Since this parabola opens upward, the vertex will be the lowest point. The x-value of the vertex is found by  -b/(2a).

a = 2    b = -8     --->     -(-8)/(2·2)  =  8/4  =  2

f(4) = 2(2)² - 8(2) + 19  =  11     <---  The minimum value of the function.

geno3141 Oct 30, 2014

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