If the adjacent is 60" and the opposite is 5" how long is the hypotenuse

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Guest May 7, 2014

+33654

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Best Answer

Use the Pythagoras theorem:

$hypotenuse=\sqrt{adjacent^2+opposite^2}$

Alan May 7, 2014

Alan · Answer 1 · 2014-05-07T11:22:03

Use the Pythagoras theorem:

$hypotenuse=\sqrt{adjacent^2+opposite^2}$