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if the number bunnies doubles every day and , on day 1 ,you start with 25 bunnies , what exponential equation best models this scenario?

 Dec 17, 2014

Best Answer 

 #2
avatar+23254 
+5

If the number of bunnies doubles every day, then you always have to multiply the preceding day's number by 2.

If you use:  y  =  25·2x-1

Then:  day 1:  x = 1  --->  y  = 25·21-1  =  25·20  =  25·1  =  25

           day 2:   x = 2  --->  y  = 25·22-1  =  25·21  =  25·2  =  50

           day 3:   x = 3  --->  y  = 25·23-1  =  25·22  =  25·4  =  100

           day 4:   x = 4  --->  y  = 25·24-1  =  25·23  =  25·8  =  200

etc.

 Dec 17, 2014
 #1
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0

f(X)=25(2)x

 Dec 17, 2014
 #2
avatar+23254 
+5
Best Answer

If the number of bunnies doubles every day, then you always have to multiply the preceding day's number by 2.

If you use:  y  =  25·2x-1

Then:  day 1:  x = 1  --->  y  = 25·21-1  =  25·20  =  25·1  =  25

           day 2:   x = 2  --->  y  = 25·22-1  =  25·21  =  25·2  =  50

           day 3:   x = 3  --->  y  = 25·23-1  =  25·22  =  25·4  =  100

           day 4:   x = 4  --->  y  = 25·24-1  =  25·23  =  25·8  =  200

etc.

geno3141 Dec 17, 2014

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