(a+1)x^2 - (a^2 + 1)x + 2a^3 - 6 = 0
By inspection...let a = 0 and we have
x^2 - x - 6 = 0 factoring, we get
(x - 3) ( x + 2) = 0
And the two roots are x = 3 and x = -2
P.S.....there may be other solutions for "a"....I don't know.....perhaps someone else knows another way to obtain all of them, if there are more...!!!!