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$10((1t2)1+t4)dt$

 

Somebody who knows solve this one? 

 Dec 13, 2014

Best Answer 

 #2
avatar+33658 
+5

It's a definite integral so:

 

 definite integral:

.

 Dec 14, 2014
 #1
avatar+23254 
+5

According to  www.wolframalpha.com/calculators/integral-calculator

the answer is:  [ log(t² + √2t + 1) - log(-t² + √2t - 1) ] / [ 2√2 ]

 Dec 14, 2014
 #2
avatar+33658 
+5
Best Answer

It's a definite integral so:

 

 definite integral:

.

Alan Dec 14, 2014

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