It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90m/s2 in 12s. What is the initial speed of the Jaguar before it began to skid?
Using the formula: d = ½at² + v0t
---> 290 = ½(-3.90)(12)² + v0(12)
---> 290 = -280.8 + 12v0
---> 570.8 = 12v0
---> 47.6 m/s
