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Joelle has a test score of 75% on a test with a mean of 62%. To get into SAIT, she needs to be in the top 20% of those who took the test. What is the largest standard deviation, to the nearest tenth, that will allow Joelle to be in the top 20%?

 May 17, 2014

Best Answer 

 #1
avatar+33654 
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Assuming the scores obey a normal distribution the following cumulative probability graph should help:

cumprob2

This is the cumulative probability for a normal distribution with mean 0 and standard deviation of 1.

Here we have z = (Joelie's test score - mean test score)/standard deviation

We can see from the graph that to get into the top 20% (ie reach a cumulative probability of 0.8) z must be at least 0.842.  So:

0.842 = (0.75 - 0.62)/stddev

stdev=(0.750.62)0.842stdev=0.1543942992874109

So the standard deviation is 0.154 or 15.4%.

At least, I think this is what you are after!

 May 18, 2014
 #1
avatar+33654 
+5
Best Answer

Assuming the scores obey a normal distribution the following cumulative probability graph should help:

cumprob2

This is the cumulative probability for a normal distribution with mean 0 and standard deviation of 1.

Here we have z = (Joelie's test score - mean test score)/standard deviation

We can see from the graph that to get into the top 20% (ie reach a cumulative probability of 0.8) z must be at least 0.842.  So:

0.842 = (0.75 - 0.62)/stddev

stdev=(0.750.62)0.842stdev=0.1543942992874109

So the standard deviation is 0.154 or 15.4%.

At least, I think this is what you are after!

Alan May 18, 2014

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