Joelle has a test score of 75% on a test with a mean of 62%. To get into SAIT, she needs to be in the top 20% of those who took the test. What is the largest standard deviation, to the nearest tenth, that will allow Joelle to be in the top 20%?
Assuming the scores obey a normal distribution the following cumulative probability graph should help:
This is the cumulative probability for a normal distribution with mean 0 and standard deviation of 1.
Here we have z = (Joelie's test score - mean test score)/standard deviation
We can see from the graph that to get into the top 20% (ie reach a cumulative probability of 0.8) z must be at least 0.842. So:
0.842 = (0.75 - 0.62)/stddev
stdev=(0.75−0.62)0.842⇒stdev=0.1543942992874109
So the standard deviation is 0.154 or 15.4%.
At least, I think this is what you are after!
Assuming the scores obey a normal distribution the following cumulative probability graph should help:
This is the cumulative probability for a normal distribution with mean 0 and standard deviation of 1.
Here we have z = (Joelie's test score - mean test score)/standard deviation
We can see from the graph that to get into the top 20% (ie reach a cumulative probability of 0.8) z must be at least 0.842. So:
0.842 = (0.75 - 0.62)/stddev
stdev=(0.75−0.62)0.842⇒stdev=0.1543942992874109
So the standard deviation is 0.154 or 15.4%.
At least, I think this is what you are after!