Let a=2n+1, b=2n^2 ^2n and c=2n^2 +2n+1.
Pick one natural number n and verify that the corresponding values of a, b and c form a Pythagorean triple
If you let n = 5:
a = 2n + 1 ---> a = 2(5) + 1 = 11
b = 2n² + 2n ---> 2(5)² + 2(5) = 60
c = 2n² + 2n + 1 ---> 2(5)² + 2(5) + 1 = 61
Now, verify that 11² + 60² = 61²
