100=10×log10(z10−12) I know the answer is 10−2 but how do I get to it? Thank you.
100 = 10 · log( z / 10^-12)
100 = 10 · log( 10^12 · z )
100 = 10 · [ log( 10^12) + log( z ) ] (When numbers are multiplied, the logs are added.)
100 = 10 · [ 12 · log( 10 ) + log( z ) ] (Exponents come out as multipliers.)
100 = 10 · [ 12 + log( z ) ] (log( 10 ) = 1 ---> 12 · log( 10 ) = 12 · 1 = 12 )
100 = 120 + 10 · log( z ) (Distribute the 10.)
-20 = 10 · log( z ) (Subtract 120 from both sides.)
-2 = log( z ) (Divide both sides by 10.)
---> z = 10^-2 (Switch from log form to exponential form.)