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100=10×log10(z1012) I know the answer is 102 but how do I get to it? Thank you.

 Nov 7, 2014

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 #2
avatar+118703 
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100=10×log10(z1012)10=log10(z1012)1010=10log10(z1012)1010=z10121010×1012=zz=101012z=102

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 Nov 8, 2014
 #1
avatar+23254 
+5

100  =  10 · log( z / 10^-12)  

100  =  10 · log( 10^12 · z ) 

100  =  10 · [ log( 10^12) + log( z ) ]                      (When numbers are multiplied, the logs are added.)

100  =  10 · [ 12 · log( 10 ) + log( z ) ]                    (Exponents come out as multipliers.)

100  =  10 · [ 12 + log( z ) ]                                    (log( 10 ) = 1   --->    12 · log( 10 )  =  12 · 1 =  12 )

100  =  120 + 10 · log( z )                                       (Distribute the 10.)

-20  =  10 · log( z )                                                 (Subtract 120 from both sides.)

-2  =  log( z )                                                         (Divide both sides by 10.)

--->   z  =  10^-2                                                   (Switch from log form to exponential form.)

 Nov 7, 2014
 #2
avatar+118703 
+5
Best Answer

100=10×log10(z1012)10=log10(z1012)1010=10log10(z1012)1010=z10121010×1012=zz=101012z=102

Melody Nov 8, 2014

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