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Define $E(a,b,c) = a \times b^c$. What positive value of $r$ is the solution to the equation $E(r,r,3) = 625$?

 Nov 6, 2014

Best Answer 

 #1
avatar+23254 
+5

E(r, r, 3)  =  625  =  r x r^3  =  r^4

                     625  =  r^4

Find the fourth root of both sides:

                    625^(1/4)  =  r

                           --->   r  =  5

 Nov 6, 2014
 #1
avatar+23254 
+5
Best Answer

E(r, r, 3)  =  625  =  r x r^3  =  r^4

                     625  =  r^4

Find the fourth root of both sides:

                    625^(1/4)  =  r

                           --->   r  =  5

geno3141 Nov 6, 2014

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