There are 5% fewer girls than boys in a badminton club. Given that there are 4 more boys than girls, find the total number of members in the club.
Hint: Let the total number of boys be 100%
+128475 4 boys must represent 5% of the club
So....the total members must be 4 / 5% 4/.05 = = 80
+318 Wait I did it wrong
Let X be the no of boys
No of girls = 0.95X
Also as per question
X = 4 + 0.95X
0.05X = 4
X= 80
No of girls= 0.95 X = 76
Total members in club = 80+76 = 156
Bold=Correct
+313 no. of boys = x ----------------(1)
no. of girls = x -5%*x
= x -5/100*x
=x-x/20
=19x/20------------------(2)
no. of boys = 19x/20 + 4 ----------------(3)
eqn (1) and (3) are equal to each other
x = 19x/20 + 4
x -19x/20 = 4
x = 4*20
x = 80 (no. of boys)
no. of girls = 80*19/20
=4*19 =76
total no of members in club = 80+76
total no of members in club = 156
