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Three plastic pipes, each of diameter 10 cm, are held together by straps. Find the length of each strap to the nearest centimeter.

Please show steps,

Thank you for the help.

 Nov 10, 2014

Best Answer 

 #2
avatar+23254 
+5

Let A, B, and C be the centers of the three circles.

The distance from A to B is a straight-line distance that included the radius of the circle A and the radius of the circle B; thus, it will be 10 cm long. So will the distances from A to C and B to C, for a total distance of 30 cm.

These distances, from A to B, B to C, and C to A, are the same lengths as the lengths of the straps which are not touching the circles.

Now for the distances that wrap around the circles: for circle A, the straps wraps around 1/3 of the pipe, so its length will be 1/3 of the circumference of the circle:  (1/3)(2·π·r)  =  (1/3)(2·π·5)  =  (1/3)(10π).

Similarly for wrapping around circles B and C. (1/3)(10π) + (1/3)(10π) + (1/3)(10π)  =  10π

Total length for each:  (10π + 30) cm

Total for both:  (20π + 60) cm

[For each, the length will be one circumference of a circle plus three diameters.]

 Nov 10, 2014
 #1
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0

Well, both straps are the same size! Lucky you.

This is an iffy question for me so may be wrong although i will have a go at it.

I'm going to say you need 1/3 of one circle x3 [So basically the circumference of the circle) and guess rx3

C = 2πxr

so C = 2xπx5 which is C = 31.4159265358979324

remember C = Circumference so 31.4159265358979324

5x3 = 15

15 + 31.4159265358979324 = 46.4159265358979324cm

Probably wrong however so wait for a better answer.

 Nov 10, 2014
 #2
avatar+23254 
+5
Best Answer

Let A, B, and C be the centers of the three circles.

The distance from A to B is a straight-line distance that included the radius of the circle A and the radius of the circle B; thus, it will be 10 cm long. So will the distances from A to C and B to C, for a total distance of 30 cm.

These distances, from A to B, B to C, and C to A, are the same lengths as the lengths of the straps which are not touching the circles.

Now for the distances that wrap around the circles: for circle A, the straps wraps around 1/3 of the pipe, so its length will be 1/3 of the circumference of the circle:  (1/3)(2·π·r)  =  (1/3)(2·π·5)  =  (1/3)(10π).

Similarly for wrapping around circles B and C. (1/3)(10π) + (1/3)(10π) + (1/3)(10π)  =  10π

Total length for each:  (10π + 30) cm

Total for both:  (20π + 60) cm

[For each, the length will be one circumference of a circle plus three diameters.]

geno3141 Nov 10, 2014

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